数列极限
等差数列 an = a1 + (n − 1)d $$ S_{n}=\frac{n}{2}(2a_{1}+(n-1)d)=\frac{n}{2}(a_{1}+a_{n}) $$ 等比数列 an = a1rn − 1 $$ S_{n}= \left\{ \begin{gather}{} na_{1}, &r=1\\ \frac{a_{1}(1-r^n)}{1-r}, &r\neq 1 \end{gather} \right. $$
常见数列前n项和
$$ \sum^{n}_{k=1}k=1+2+3+\dots+n=\frac{n(n+1)}{2} $$ $$ \sum^{n}_{k=1}k^2=1^2+2^2+3^2+\dots+n^2=\frac{n(n+1)(2n+1)}{6} $$ $$ \sum^{n}_ {k=1} \frac{1}{k(k+1)}=\frac{1}{1\times2}+\frac{1}{2\times 3}+\frac{1}{3 \times 4}+\dots+\frac{1}{n(n+1)}=\frac{n}{n+1} $$
重要数列,单调递增: $$ \lim_{ n \to \infty } \left( 1+\frac{1}{n} \right)^n=e $$
算术平均值大于集合平均值 $$ \frac{a+b}{2}\geq \sqrt{ ab } $$
- 原数列收敛,子列也收敛
- 子列发散,原数列发散
- 两子列收敛到不同极限,原数列发散
limn → ∞an = 0 ⇔ limn → ∞|an| = 0
limx → x0f(x) = A ⇔ limx → x0|f(x)| = |A| 脱帽法 limn → ∞xn > a ⇒ xn > a 戴帽法 xn ≥ a ⇒ limn → ∞xn ≥ a
和差化积 $$ \sin \alpha +\sin \beta=2\sin\frac{\alpha+\beta}{2}\cos \frac{\alpha-\beta}{2} $$ $$ \sin \alpha -\sin \beta=2\sin\frac{\alpha-\beta}{2}\cos \frac{\alpha+\beta}{2} $$ $$ \cos \alpha +\cos \beta=2\cos\frac{\alpha+\beta}{2}\cos \frac{\alpha-\beta}{2} $$ $$ \cos \alpha -\cos \beta=-2\sin\frac{\alpha+\beta}{2}\sin \frac{\alpha-\beta}{2} $$
正余弦公式 sin (α ± β) = sin αcos β ± cos αsin β cos (α + β) = cos αcos β ∓ sin αsin β $$ \tan(\alpha\pm \beta)=\frac{\tan \alpha \pm \tan \beta}{1\mp \tan \alpha \tan \beta} $$
海涅定理(归结原则)
∃limx → x0f(x) = A ⇔ ∀xn∃limxn → x0f(xn) = A
夹逼准则
$$ n \cdot u_{\min}\leq \sum^{n}_{i=1}u_{i}\leq n\cdot u_{\max} $$ $$ 1\cdot u_{\max}\leq \sum^{n}_{i=1}u_{i}\leq n\cdot u_{max} $$ $$ \lim_{ n \to \infty }n^ \frac{1}{n}=e^0 =1 $$
$$ \lim_{ n \to \infty } \sqrt[n]{\sum^{m}_{i=1}a_{i}^n}=\max \{a_{m}\} $$
$$ 0<a<b \Leftrightarrow 0<\frac{1}{b} <\frac{1}{a} ,\ \lim_{ n \to \infty } (a^{-n}+b^{-n})^ \frac{1}{n}=\frac{1}{a} $$
|a ± b| ≤ |a| + |b| |a1 ± a2 ± a3 ± … ± an| ≤ |a1| + |a2| + … + |an| ||a|−|b|| ≤ |a − b| $$ \sqrt{ ab }\leq \frac{a+b}{2}\leq \sqrt{ \frac{a^2 +b^2}{2}}, \ (a,b\geq 0) $$
$$ |ab|\leq \frac{a^2+b^2}{2} $$
$$ \frac{u_{n}}{n}=u_{n} \cdot \frac{1}{n}\leq \frac{u_{n}^2 +\frac{1}{n}^2}{2}, \ u_{n} > 0 $$
$$ \sqrt[3]{ abc }\leq \frac{a+b+c}{3}\leq \sqrt{ \frac{a^2 +b^2+c^2}{3}}, \ (a,b,c\geq 0) $$
a ≥ b ≥ 0, am ≥ bm(m > 0), am ≤ bm(m < 0)
$$ 0<a<x<b, \ 0<c<y<d \ \Rightarrow \frac{c}{b}< \frac{y}{ x} < \frac{d}{a} $$
$$ \sin x < x < \tan x \left( 0< x < \frac{\pi}{2} \right) $$ sin x < x(x > 0)
$$ x<\tan x< \frac{4}{\pi}x $$ $$ \sin x> \frac{2}{\pi}x $$ arctan x < x < arcsin x ex ≥ x + 1 ln x < x − 1 $$ \frac{1}{1+x}<\ln\left( 1+ \frac{1}{x} \right)< \frac{1}{x} $$ $$ \frac{x}{1+x}<\ln(1+x)<x $$
压缩映射 0 ≤ |xn + 1 − a| ≤ k|xn − a|
单调有界必有极限
$$ x_{x+1}-x_{n}> o r <0, \ \frac{x_{n+1}}{x_{n}}> or <1 $$
f′(x) > 0, x2 > x1单增, x2 < x1单减 f′(x) < 0, 不单调