#!/usr/bin/env python3 import glob import os from cryptography import x509 from cryptography.hazmat.backends import default_backend from cryptography.hazmat.primitives import serialization from cryptography.hazmat.primitives.asymmetric import rsa from scapy.allimport * from scapy.layers.tls.allimport TLS from scapy.layers.tls.cert import Cert from scapy.layers.tls.handshake import TLSCertificate
defextract_certs_from_pcap(pcap_path): """Extracts TLS certificates from a PCAP file.""" packets = rdpcap(pcap_path) cert_list = []
for pkt in packets: if pkt.haslayer(Raw): raw = pkt[Raw].load try: tls_parsed = TLS(raw) tls_cert_layer = tls_parsed.getlayer(TLSCertificate) if tls_cert_layer: for _, x509_wrapper in tls_cert_layer.certs: cert_list.append(x509_wrapper) print(f"[+] Extracted Certificate: {x509_wrapper.subject}") except Exception: continue return cert_list
defget_rsa_modulus(cert_obj): """Extracts the RSA modulus from a Scapy Cert object.""" try: ifnotisinstance(cert_obj, Cert): returnNone pubkey_bytes = cert_obj.pubKey.der public_key = serialization.load_der_public_key(pubkey_bytes)
ifisinstance(public_key, rsa.RSAPublicKey): return public_key.public_numbers().n except Exception as e: print(f"[-] Error parsing public key: {e}") returnNone
deffind_matching_key(target_modulus, keys_directory): """Finds a PEM private key in a directory matching the given modulus.""" print(f"[*] Searching for matching key in {keys_directory}...")
for key_file in glob.glob(os.path.join(keys_directory, "*")): try: withopen(key_file, "rb") as f: private_key = serialization.load_pem_private_key( f.read(), password=None, backend=default_backend() )
Posted onInctfDisqus: Word count in article: 246Reading time ≈1 mins.
An encryption service encrypts plaintext, but blocks encryption of
the impossible_flag_user string. Exploit the ECB mode
implementation to forge an encrypted token that decrypts to this
forbidden value.
Vulnerability
The service uses AES in ECB mode, which has critical
weakness: identical plaintext blocks produce identical ciphertext
blocks. By crafting specific payloads, we can:
Encrypt the first 16 bytes of the target string
Encrypt padding-aligned subsequent bytes
Concatenate the cipher blocks to forge a valid token
Exploit Strategy
The target user is: impossible_flag_user (23 bytes)
Block 1: Encrypt impossible_flag_ (16
bytes) → get first cipher block
Block 2: Encrypt user + PKCS#7 padding
→ get second cipher block
Combine: Concatenate blocks to form forged token →
decrypt equals target
Posted onInctfDisqus: Word count in article: 175Reading time ≈1 mins.
Socket challenge requiring automation to solve 500 arithmetic
problems programmatically. Use Python with pwntools to interface with
the remote service and automate the solution.
Key Considerations
Library: pwntools for socket communication
Custom delimiter: Uses \r\n instead of
standard \n
Approach: Parse math expressions dynamically and
compute answers
Posted onInctfDisqus: Word count in article: 1.2kReading time ≈4 mins.
Challenge Description
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Our web server was compromised again and we aren't really sure what the attacker was doing. Luckily, we only use HTTP and managed to capture network traffic during the attack! Can you figure out what the attacker was up to?
We start by analyzing the PCAP file to identify interesting HTTP
interactions. Using a simple Scapy script, we can filter for
200 OK responses to see what the server was returning.
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#!/usr/bin/env python3 from scapy.allimport *
PCAP_FILE = "web_shell.pcap"
packages = rdpcap(PCAP_FILE) for i, p inenumerate(packages): if p.haslayer(Raw): raw = p[Raw].load ifb"200 OK"in raw: try: print(f"[*] Packet {i+1} | Length: {len(raw)}") print(raw.decode()) print("-" * 20) except: continue
In the output, we notice a file upload form and a confirmation that
owned.php was uploaded:
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[*] Packet 16640 HTTP/1.1200 OK ... <body> <form enctype="multipart/form-data" action="uploader.php" method="POST"> <p>Upload your file</p> <input type="file" name="uploaded_file"></input><br /> <input type="submit" value="Upload"></input> </form> </body> </html> The file owned.php has been uploaded
Checking the preceding packets (around index 16638), we find the
content of the uploaded owned.php.
2. Analyzing the Malicious
Web Shell
The uploaded file owned.php contains an obfuscated PHP
script.
By removing the noise (replacing [Z and
eq), we can reconstruct the logic. It's a sophisticated web
shell (similar to Behinder or Godzilla) that uses XOR encryption and
Zlib compression for C2 traffic.
Now that we have the key (81aebe18) and the protocol
markers, we can decrypt the subsequent traffic. We notice the attacker
is executing commands like ls and xxd to read
a file named y_flag_here.txt one byte at a time.
Example of a decrypted request:
chdir('/var/www/html/uploads');@error_reporting(0);@system('xxd -p -l1 -s31 ../y_flag_here.txt 2>&1');
4. Automated Flag
Reconstruction
To get the full flag, we need to iterate through all packets, decrypt
the requests to find the offset (-s parameter in
xxd), and decrypt the responses to find the hex value of
the character at that offset.
#!/usr/bin/env python3 """ Scapy HTTP/Webshell Traffic Analyzer ------------------------------------ A specialized utility for extracting and decrypting payloads from PCAP files, targeting traffic typical of PHP webshells (e.g., Behinder, AntSword). Includes logic for XOR decryption, Zlib decompression, and flag assembly. """
import base64 import re import urllib.parse import zlib
defextract_flag_fragment(raw_text): """ Parses decrypted output to identify flag fragments extracted via 'xxd'. Expects 'xxd -p -l1 -s[offset]' in request and 2-char hex in response. """ global current_offset raw_text = raw_text.strip() ifnot raw_text: return
# Match Request: Extract offset from xxd command if"xxd -p -l1 -s"in raw_text: match = re.search(r"-s(\d+)", raw_text) ifmatch: current_offset = int(match.group(1))
# Match Response: If we have an offset, convert hex response to char elif current_offset != -1and re.match(r"^[0-9a-fA-F]{2}$", raw_text): try: char = bytes.fromhex(raw_text).decode("utf-8") flag_data[current_offset] = char print( f"[\033[92m+\033[0m] Fragment Found: Offset {current_offset:02} -> '{char}'" ) except Exception as e: print(f"[-] Decode error: {e}") finally: current_offset = -1
defprocess_pcap(packets, regex): """Iterates through packets, searching for encrypted payloads via regex.""" print(f"[*] Analyzing {len(packets)} packets...")
for i, p inenumerate(packets): if p.haslayer(Raw): raw_payload = p[Raw].load match = re.search(regex, raw_payload) ifmatch: decrypted = decrypt_payload(match.group(1)) print(f"[*] Packet {i + 1} matched.") # print(f"Raw: {match.group(1)[:50]}...") # Debug print(f"Decrypted: {decrypted}")
extract_flag_fragment(decrypted) print("-" * 30)
defprint_final_flag(): """Sorts fragments by offset and prints the assembled flag.""" ifnot flag_data: print("\n[-] No flag fragments found in the analyzed packets.") return
sorted_chars = [flag_data[k] for k insorted(flag_data.keys())] final_flag = "".join(sorted_chars)
defcheck_packet_by_content(packets, content): """Heuristic search for specific raw bytes in a PCAP.""" for i, p inenumerate(packets): if p.haslayer(Raw) and content in p[Raw].load: print(f"[*] Content found in Packet {i + 1}") print(p[Raw].load.decode(errors="ignore"))
# --- Main Execution ---
if __name__ == "__main__": try: # Load necessary layers load_layer("tls")
# Load PCAP pkts = rdpcap(PCAP_FILE)
# Regex to capture content between specific webshell markers payload_regex = KH + b"(.+?)" + KF
Posted onEdited onInctfDisqus: Word count in article: 118Reading time ≈1 mins.
Identify the flag hidden within error messages of ICMP traffic
captured in a PCAP file.
Vulnerability
ICMP packets (ping replies) can carry data in their payload. The flag
is exfiltrated through ICMP echo replies. ICMP is often overlooked as a
potential data exfiltration channel.
Solution
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#!/usr/bin/env python3 from scapy.allimport rdpcap from scapy.layers.inet import ICMP
packets = rdpcap("error_reporting.pcap") flag = b""
for p in packets: # ICMP type 0 = Echo Reply (responses to ping requests) if p.haslayer(ICMP) and p[ICMP].type == 0and p.haslayer("Raw"): flag += p["Raw"].load
withopen("flag.jpg", "wb") as f: f.write(flag)
print("[+] Extracted data saved to flag.jpg")
The extracted data is a JPG image containing the flag.